A particularly long traffic light on your morning commute is green 17% of the time that you approach it. Assume that each morning represents an independent trial. Over 20 mornings, what is the probability that the light is green on exactly 4 day

Step-by-step explanation:

Assuming that we are only trying to calculate the probability of the light being green ONLY on day 4 then it would be the exact same probability as every other day, which would be 17%. Now if we are trying to calculate the probability of the light being green on the first consecutive 4 days then we would need to multiply this probability (in decimal form) four times for the four days like so...

0.17 * 0.17 * 0.17 * 0.17 = x

0.00083521 = x   ... times by 100 to get percentage

0.00083521 * 100 = 0.0835%

So the probability of the light being green 4 days in a row during your commute is 0.0835%

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9