What is the distance between-3.8 and 4.2

2.23606797749979

Midpoint

(2,−4.5)

Slope

0.5

x intercept

11.00

y intercept

−5.50

Step-by-step explanation:

d = √  ((X2-X1)2+(Y2-Y1)2)

d = √(1-3)2+(-5--4)2

d = √((-2)2+(-1)2)

d = √(4+1)

d = √5

The distance between the points is 2.23606797749979

The midpoint of two points is given by the formula

Midpoint= ((X1+X2)/2,(Y1+Y2)/2)

Find the x value of the midpoint

Xm=(X1+X2)/2

Xm=(3+1)/2=2

Find the Y value of the midpoint

Ym=(Y1+Y2)/2

Ym=(-4+-5)/2=-4.5

The midpoint is: (2,-4.5)

Graphing the two points, midpoint and distance

P1 (3,-4)

P2 (1,-5)

Midpoint (2,-4.5)

The length of the black line is the distance between the points (2.23606797749979)

Find the slope of the line connecting the two points

Slope =  (Y2-Y1)  =  (-5--4)  =  (-1)  = 0.5

(X2-X1)(1-3)(-2)

Find the equation of the line passing through the two points

The general equation for a straight line is

y = mx + b

Where m represents the slope of the line which we found in the previous step to be 0.5

y = 0.50x + b

We substitute x and y for the values from one of our points (3,-4)

-4 = .50×3 + b

-4 = 1.50 + b

-4-1.50 = b

-5.50 = b

Knowing both b and m, we can contruct the equation of the line

y= 0.50x-5.50

X and Y intercepts

The x-intercept is a point on the graph where y is zero

Using the equation we found in the previous step and substituting zero for y

y= 0.50x-5.50

0= 0.50x-5.50

-0.50x= -5.50

x= -5.50/-0.50 = 11.00

The x intercept for this straight line is 11.00

The y-intercept is a point on the graph where x is zero

Using the equation we found in the previous step and substituting zero for x

y= 0.50×0-5.50

y= -5.50

The y intercept for this straight line is -5.50

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: