Point K is located at (7,4) in the coordinate plane. Which of the following transformations will result in the image of K. K (4,-7)? Select all that apply.
K' =T<3,11> (K)
o-azie (K))
K = Ry-axis (Re-
K' = Ry-z (K)
K' =T<-3,-11» (K)
K' = R0g0° (K)
K' = R0270° (K)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

whats the

the answer is 2/54

step-by-step explanation: