Tn =1-3n

Next 3 terms

The next three terms are (-3n - 2), (-3n - 5), (-3n - 8)

Step-by-step explanation:

∵ T(n) = 1 - 3n, where

To find the next three terms substitute n by n + 1, n + 2, n + 3

∵ n = n + 1

∴ T(n + 1) = 1 - 3(n + 1)

∴ T(n + 1) = 1 - 3(n) - 3(1)

∴ T(n + 1) = 1 - 3n - 3

∴ T(n + 1) = -3n - 2

∴ T(n + 1) = -3n -2

∵ n = n + 2

∴ T(n + 2) = 1 - 3(n + 2)

∴ T(n + 2) = 1 - 3(n) - 3(2)

∴ T(n + 2) = 1 - 3n - 6

∴ T(n + 2) = -3n - 5

∴ T(n + 2) = -3n -5

∵ n = n + 3

∴ T(n + 3) = 1 - 3(n + 3)

∴ T(n + 3) = 1 - 3(n) - 3(3)

∴ T(n + 3) = 1 - 3n - 9

∴ T(n + 3) = -3n - 8

∴ T(n + 3) = -3n - 8

∴ The next three terms are (-3n - 2), (-3n - 5), (-3n - 8)

it would open into a square depending on the type of envelope i’m not sure about the second part