PLEASE HELP Write the equation in standard form of the line that passes through (4,3) parallel to 2x-y = -5


2x+y=11

Step-by-step explanation:

First, put 2x-y=-5 into slope intercept form (makes it easier)

y=-2x-5

Now, parallel lines have different y intercepts, but the same slope.

so, put the new line as y=-2x+b (b is a placeholder)

now, we need to find the y intercept, and you can do that  by placing (4,3) into the equation of y=-2x+b

3=-2(4)+b

3=-8+b

11=b

New line will be y=-2x+11

HOWEVER, the question asks for the lines to be in standard form

add 2x on both sides

2x+y=11

Hope this helps!

idk

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