Find three consecutive odd integers such that the sum of twice the largest and the smallest is 101.

The sum of any set of consecutive odd numbers starting with 1 is always equal to the square of the number of digits that were added together. Sum of first two odd numbers = 1 + 3 = 4 (= 2 x 2). Sum of first three odd numbers = 1 + 3 + 5 = 9 (= 3 x 3). Sum of first four odd numbers = 1 + 3 + 5 + 7 = 16 (= 4 x 4).

Step-by-step explanation:

hope this helps you ✌️

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate