If x^2+x =3^2/3+3^-2/3 then prove that 3x^3+9x-8=0

x^2 + 2 = 3^2/3 + 3^-2/3

x^2 = 3^2/3 + 3^-2/3 - 2

x = √(3^2/3 + 3^-2/3 - 2)

x = 0.748888296

Substitute for x in 3x^3 + 9x - 8:

3( 0.748888296)^3 + 9( 0.748888296) - 8 = 0.

So it is proved.

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y