The digits of a two-digit number differ by 2. If the digits are interchanged and the resulting number is added to the original number, we get 154. What is the original
number?
a) 46 or 64
b) 24 or 42 c) 86 or 68 d) 75 or 57

Difference between the digits = 2

Sum of the original number and the number formed by reversing the digits is 154.

original  number

Let the digit at ten's place be x and digit at one's place be y.

The number = 10x + y or xy.

Difference between the digits = 2

→ x - y = 2

→ x = 2 + y -- equation (1)

And,

Sum of the original number and the number formed by reversing the digits is 154.

Number formed by reversing the digits = 10y + x.

According to the above condition,

→ 10x + y + 10y + x = 154

→ 11x + 11y = 154

Substitute x value from equation (1).

→ 11(2 + y) + 11y

→ 22 + 11y + 11y = 154

→ 22y + 22 = 154

→ 22y = 154 - 22

→ 22y = 132

→ y = 132/22

→ y = 6

Substitute the value of y in equation (1).

→ x = 2 + 6

→ x = 8

The number = xy = 86

reversed number = yx = 68

Therefore, the required number will be 86 or 68 (Option - C).

I hope it will help you.

Regards.

→ 11(2 + y) + 11y

→ 22 + 11y + 11y = 154

→ 22y + 22 = 154

→ 22y = 154 - 22

→ 22y = 132

→ y = 132/22

→ y = 6

Step-by-step explanation:

x = -2

y = 848

step-by-step explanation:

plug in the numbers

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3