Find the value of X and Y if (2x + 3) + i(x – 2y) = 5 – 7i

x = 1, y = 4

Step-by-step explanation:

Given

(2x + 3) + i(x - 2y) = 5 - 7i

Equate the real parts on both sides

2x + 3 = 5 ( subtract 3 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

Equate the coefficients of the imaginary terms

x - 2y = - 7 , that is

1 - 2y = - 7 ( subtract 1 from both sides )

- 2y = - 8 ( divide both sides by - 4 )

y = 4

d is the only accurate one

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: