Abcd is a cyclic quadrilateral. o is the center of the circle ∠bad = 40°,then angle BCD=?,m(arc BCD) =?,m( arc BAD)=?

m∠BCD = 140°

m(arc BCD) = 80°

m(arc BAD) = 280°

Step-by-step explanation:

Let us use these facts to solve the question

∵ ABCD is a cyclic quadrilateral in circle O

∵ ∠BAD and ∠BCD are opposite angles

→ By using the 1st fact above

∴ m∠BAD + m∠BCD = 180°

∵ m∠BAD = 40°

∴ 40° + m∠BCD = 180°

→ Subtract 40° from both sides

∴ 40° - 40° + m∠BCD = 180° - 40°

∴ m∠BCD = 140°

∵ Arc BCD subtended the inscribed ∠BAD

→ By using the 2nd fact above

∴ m(arc BCD) = 2(m∠BAD)

∵ m∠BAD = 40°

∴ m(arc BCD) = 2(40°)

∴ m(arc BCD) = 80°

∵ Arc BAD subtended the inscribed ∠BCD

→ By using the 2nd fact above

∴ m(arc BAD) = 2(m∠BCD)

∵ m∠BCD = 140°

∴ m(arc BAD) = 2(140°)

∴ m(arc BAD) = 280°.

we don't have enough info to solve this

4 adults and 12 babies

step-by-step explanation:

4 x 7 = 28

12 x 15 = 180

180 + 28 =208

4 x 3 = 12