What are the zeros of y=(x+2)(x-3)^2
And what is the step by step process on how to find it

The zeros are -2 and 3

Step-by-step explanation:

Set each equation equal to zero

so...

x + 2 = 0

x - 3 = 0

and solve for x

if you don't know how to solve for x...

x + 2 = 0      try to single out x by moving the 2 to the other side

x = -2           the sign changes because it moves to the other side of the equal sign.

There you have it: -2 and 3

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement