The sum of three consecutive even integers is 72 Letx represent the first integer, x + 2 represent the second integer, and x + 1 represent the third integer
Which equation can be used to find the first integer?
2x + 64 = 72
3x + 72 - 2x + 6
3x + 2x + 6
3x + 6 = 72

3x+6=72

Step-by-step explanation:

1.st integer is x

2.nd is  x+2

Thrd is x+4

So the sum is x+x+2+x+4=3x+6=72

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

20%

step-by-step explanation: