Question 2 (1 point) Write an equation of a parabola in vertex form that passes through (8,
25) and has vertex (5,-2).
(Use the ^ symbol to show an exponent. Example: x2 = x^2)
Blank 1:

Step-by-step explanation:

y = a(x-h)^2+k   ← vertex form of parabola equation with vertex (h, k)

So:

y = a(x-5)^2 + (-2)    ←  vertex form of our parabola equation

Parabola goes through (8, 25) so if x=8 then y=25

25 = a(8-5)^2 - 2

25 +2  = a(3)^2 - 2 +2

27 = 9a

a = 3

That means, the equation of a parabola in vertex form that passes through (8,  25) and has vertex (5, -2):

                                             y = 3(x - 5)^2 - 2

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: