Big problem. Need the answer ASAP!! Please

9514 1404 393

  E.  36.8 ft

  F.  59 ft

  G.  3.5 ft or 114.5 ft

Step-by-step explanation:

E. Put x=60 in the equation and do the arithmetic.

  h = -0.01·60^2 +1.18·60 +2 = -36 +70.8 +2 = 36.8

The height is 36.8 feet when the ball is 60 feet downfield.

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F. The vertex of expression ax^2 +bx +c is x = -b/(2a). Here, that is ...

  x = -(1.18)/(2(-0.01)) = 59

The ball has traveled 59 feet downfield when it reaches its maximum height.

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G. To find the downfield distance for a height of 6 feet, we set h=6 and solve for x.

  6 = -0.01x^2 +1.18x +2

  0.01x^2 -1.18x +4 = 0 . . . put in standard form

  x^2 -118x +400 = 0 . . . . . multiply by 100 to get rid of decimals

  x = (118 ± √(118² -4(1)(400)))/(2) = 59 ±√3081

  x ≈ 59 ± 55.5 ft = {3.5 ft, 114.5 ft}

The ball will be 6 ft high at distances of 3.5 and 114.5 ft downfield.

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315