Write the equation of a line parallel to 2x - y = 10 that passes through the point (3,-2)

y=2 x+15

Step-by-step explanation:

Given the slope of a line and a point it passes through, we can use the point-slope formula to determine the equation of the line.

m = (y1-y2) / (x1-x2)

2 = (y-11) / (x- (-2)) = (y-11) / (x+2)

Multiply both sides by (x+2) give 2(x+2) = y-11

2x+4 = y-11

2x+4+11 = y

2x+15 = y

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

step-by-step explanation: