A triangle has one angle that measures 5º more than twice the smallest angle, and the largest angle measures 11° less than 3 times the measure of the smallest angle. Find the measures of the three angles.

A = 82, B = 67 and C = 31

Step-by-step explanation:

Let the angles in the given  triangle be;

              A, B and C;

A is the largest angle and C is the smallest angle;

        B = 5 + 2C i

        A = 3C - 11   ii

A+ B + C = 180°   iii

   Now, if we add equation i and ii;

            A + B = 5+2C + 3C - 11

            A+B = 5C - 6   iv

Now insert equation iv into iii;

            5C -6 + C = 180

               6C = 180 + 6

               6C = 186

                   C = 31

A = 3C - 11 = 3(31) - 11 = 93 - 11  = 82

B = 5 + 2C = 5 + 2(31) = 67

A = 82, B = 67 and C = 31

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24

9 x 8 divided by (5-3)=36