Mathematics, 01.11.2020 14:50 PrisonKing3749

The variables x and y satisfy the differential equation dy/dx= (y-1)/(x+1)(x+3) It is given that y = 2 when x = 0. (i) Solve the differential equation, obtaining y in terms of x.
(ii) Explain why x can only take values that are less than 1

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The variables x and y satisfy the differential equation dy/dx= (y-1)/(x+1)(x+3) It is given that y = 2 when x = 0. (i) Solve the differential equation, obtaining y in terms of x. (ii) Explain why x can only take values that are less than 1

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The variables x and y satisfy the differential equation dy/dx= (y-1)/(x+1)(x+3) It is given that y = 2 when x = 0. (i) Solve the differential equation, obtaining y in terms of x.
(ii) Explain why x can only take values that are less than 1