A skateboarder holds onto a circular merry-go-round, which is a certain distance away from a padded wall. The platform of the merry-go-round has a 7 -foot radius and makes a complete revolution, spinning counterclockwise, every 6 seconds. Assume the point at which the merrygo-round is the shortest distance from the wall is 12 o'clock. The skateboarder lets go of the merry-go-round at the 2 o'clock position, at which time they are 29 feet from the padded wall. How long will it take the skateboarder to hit the wall? Given the same merry-go-round, assume the skateboarder lets go at the 4 o'clock position. How long will it take the skateboarder to hit the wall?

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

3 qrs + 3/2 xy hope this : /

step-by-step explanation:

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).