Identify each pair of angles as alternate interior, corresponding, alternate exterior, or none of these.

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

no its the same as every other grade

step-by-step explanation:

differentiate (x^14(x^-2)^4with respect to the variable

the parentheses don't balance in your input.

differentiate 0 with respect to

the final answer is

0

hope this

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft