Person to get this question right will get brainliest: If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?

We have the following data:

n (number of moles) = 3 moles

P (pressure) = 5.6 atm

V (volume) = 12 L

T (temperature) = ? (in Kelvin)

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

The temperature is approximately 205 Kelvin

Okay so according to the formula PV=nRT

n=4

P=5.6 atm

V=12 L

R=0.08206 L atm mol-1 K-1

T=?

So, if you plug it in, you will get:-

T=PV/nR

T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)

T=204.73 K

Hope I'm right! :)

Step-by-step explanation:

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: