In a farm, ratio of number of cows to number of hens is 2:3. If the number of legs is 40 more than number of eyes, total of how many hens are there in the farm?

Step-by-step explanation:

Let the number of hens be x and the number of cows be y. For heads the equation is

x + y = 50 (head count is 50)

For legs the equation is

2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs)

From head count equation

y = 50 - x

substituting this in leg count equation we get

2x + 4(50 - x) = 144

2x + 200 - 4x = 144

-2x = 144 - 200

-2x = - 56

x = 28

Substituting in headcount equation we get

y = 50 - 28

So y = 22

So there are 28 hens and 22 cows on the farm.

28 hens

Step-by-step explanation:

Let the number of hens be x and the number of cows be y. For heads the equation is

x + y = 50 (head count is 50)

For legs the equation is

2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs)

From head count equation

y = 50 - x

substituting this in leg count equation we get

2x + 4(50 - x) = 144

2x + 200 - 4x = 144

-2x = 144 - 200

-2x = - 56

x = 28

Substituting in headcount equation we get

y = 50 - 28

So y = 22

So there are 28 hens and 22 cows on the farm.

i'm going to search it

step-by-step explanation:

answer: 1, 3 and 5 are correct

step-by-step explanation: