There are 1000 households in a town. Specifically, there are 100 households with one member, 200 households with 2 members, 300 households with 3 members, 200 households with 4 members, 100 households with 5 members, and 100 households with 6 members. Thus, the total number of people living in the town is

3300 people

Step-by-step explanation:

There are 1000 households in a town. Specifically, there are

100 households with one member

= 100 × 1 member

= 100 people

200 households with 2 members

= 200 × 2 members

= 400 people

300 households with 3 members

= 300 × 3 member

= 900 people

200 households with 4 members,

= 200 × 4 members

= 800 people

100 households with 5 members

= 100 × 5 members

= 500 people

100 households with 6 members.

= 100 × 6 member

= 600 people

Thus, the total number of people living in the town is

100 people + 400 people + 900 people + 800 people + 500 people + 600 people

= 3300 people

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !