Vicki, Jamal and Tyson are ordering subs from a shop that lets them choose the number of meats, cheeses and veggies that they want. Vicki chooses 1 meat, 2 cheeses and 5 veggies for

her sub and paid $5.70. Jamal paid $7.85 and got 3 meats, 2 cheeses and 2 veggies on his sub.

Tyson ordered 2 meats, 1 cheese and 4 veggies and paid $6.15 for his sub. How much would a

sub that had 4 meats, 2 cheeses and 3 veggies cost?

Let's define the variables:

M = cost of a meat

C = cost of a cheese.

V = cost of a veggetal.

Assuming that the cost of the subs only depends on the thins they order.

We know that:

" Vicki chooses 1 meat, 2 cheeses and 5 veggies for  her sub and paid $5.70."

M + 2*C + 5*V = $5.70

"Jamal paid $7.85 and got 3 meats, 2 cheeses and 2 veggies on his sub. "

3*M + 2*C + 2*V = $7.85

"Tyson ordered 2 meats, 1 cheese and 4 veggies and paid $6.15 for his sub."

2*M + 1*C + 4*V = $6.15

Then we have a system of 3 equations and 3 variables:

M + 2*C + 5*V = $5.70

3*M + 2*C + 2*V = $7.85

2*M + 1*C + 4*V = $6.15

The first step to solve this is isolate one of the variables in one of the equations, and then replace that in the other two.

I will isolate M in the first equation:

M = $5.70 - 2*C - 5*V

Replacing that in the other two equations we get;

3*($5.70 - 2*C - 5*V) + 2*C + 2*V = $7.85

2*($5.70 - 2*C - 5*V) + 1*C + 4*V = $6.15

Let's simplify the equations:

$17.10 - 4*C - 13*V = $7.85

$11.40 - 3*C - 6*V = $6.15

Now let's isolate other of the variables, i will isolate C in the second one:

3*C = -6*V + $11.40 - $6.15 = $5.25

C = -2*V + $1.75

Now let's replace that in the other equation and get:

$17.10 - 4*(-2*V + $1.75) - 13*V = $7.85

Now we can solve this for V:

$17.10  + 8*V - $7 - 13*V = $7.85

$10.10 - 5*V = $7.85

5*V = $10.10 - $7.85 = $2.25

V = $2.25/5 = $0.45

Now we can find the other two costs:

C = -2*$0.45 + $2.625 = $0.85

M = $5.70 - 2*$0.85 - 5*$0.45 = $1.75

Now we can answer the question:

"How much would a  sub that had 4 meats, 2 cheeses and 3 veggies cost?"

4*$1.75 + 2*$0.85 + 3*$0.45 = $10.50

The sub will cost $10.50

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

yo answer should be 6 if im not mistaken

step-by-step explanation: