An independent random sample is selected from an approximately normal population with an unknown standard deviation. Find the p-value for the given set of hypotheses and T test statistic. (a) HA: μ > 0.5, n = 21, T = 2.485 p-value > 0.100 0.050 < p-value < 0.100 0.025 < p-value < 0.050 0.010 < p-value < 0.025 0.005 < p-value < 0.010 p-value < 0.005 Determine if the null hypothesis would be rejected at α = 0.01. reject H0 fail to reject H0 Changed: Your submitted answer was incorrect. Your current answer has not been submitted. (b) HA: μ < 3, n = 17, T = 0.5 p-value > 0.100 0.050 < p-value < 0.100 0.025 < p-value < 0.050 0.010 < p-value < 0.025 0.005 < p-value < 0.010 p-value < 0.005 Determine if the null hypothesis would be rejected at α = 0.01.

(a) The correct interval is, 0.010 < p-value < 0.025. Fail to reject H₀.

(b) The correct interval is, p-value > 0.100. Fail to reject H₀.

Step-by-step explanation:

(a)

The information provided is:

Hₐ: μ > 0.5, n = 21, t = 2.485

Compute the p-value as follows:

The correct interval is, 0.010 < p-value < 0.025.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

p-value = 0.011 > α = 0.01

Fail to reject H₀.

(b)

The information provided is:

Hₐ: μ < 3, n = 17, t = 0.5

Compute the p-value as follows:

The correct interval is, p-value > 0.100.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

p-value = 0.312 > α = 0.01

Fail to reject H₀.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72