The polynomial p(x) = x^2+ax+b has distinct roots 2a and b. Find a + b.

Hello,

As 2a and b are two distinct roots of P(x) we can write the following:

Then, a=1/2 and b=-3/2

a+b=1/2-3/2=-1

thanks

Actually, we cannot simplify by b if b is different from 0 so we should take into account the specific case of b=0 but then we come up with a=-2a so a=0 and then 2a=0 et b=0 and this is not possible because it says that 2a and b are two distinct roots, so the case where b=0 is not possible so we can assume that b is different from 0 and then we can simplify b=2ab by 1=2a, so we are good. the solution is a+b=-1

step-by-step explanation:

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answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.