A rectangle has an area of 8x² and a length of 4x. Find the width of the rectangle

Hi there! :)

Recall that the formula of a rectangle is A = l × w

We are asked to solve for the width, so rewrite the equation:

A / l  = w

8x² / 4x = w

When dividing, divide the coefficients then divide the variables.

8 / 4 = 2

x² / x = x

Therefore, 8x² / 4x = 2x. The width of the rectangle is 2x units.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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35-60 students are taking math.