For a scale to pass inspection, the scale's reading can vary by at most 0.1% from the actual mass of an object on the scale. A test mass has an exact mass of 250.00 grams. In what range must the scale's reading be for the scale to pass inspection?

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

oh

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