A. No solution
Step-by-step explanation:
System of Equations
We have this system of equations:
![y=x^2+x+3](/tpl/images/0862/8878/cb2a9.png)
![y=-2x-5](/tpl/images/0862/8878/93d31.png)
To solve the system, we can substitute y from one equation into the other:
![x^2+x+3=-2x-5](/tpl/images/0862/8878/44b12.png)
Prepare the second-degree equation. Adding 2x+5:
![x^2+x+3+2x+5=0](/tpl/images/0862/8878/6e48b.png)
Simplifying:
![x^2+3x+8=0](/tpl/images/0862/8878/0d365.png)
The equation has the coefficients:
a=1, b=3, c=8
To find out the number of real solutions of the quadratic equation, we calculate the discriminant d:
![d=b^2-4ac](/tpl/images/0862/8878/53a54.png)
![d=3^2-4(1)(8)](/tpl/images/0862/8878/7c1a8.png)
![d=9-32=-23](/tpl/images/0862/8878/38b74.png)
Since the discriminant is negative, the equation has no real solutions, thus the system of equations has no real solution.
A. No solution