Please help quick!!
Given ΔΡHS & ΔCNF, find the values of x, y, and z.

Step-by-step explanation:

We know that .

Then by CPCTC, ∠P≅∠C, ∠H≅∠N, and ∠S≅∠F.

Therefore, let’s solve for each of the angle relations.

∠P≅∠C:

We know that ∠P is 36°. ∠C is (4z-32)°. Therefore:

Solve for z:

So, the value of z is 17.

∠H≅∠N

∠H is (6x-29) and ∠N is 115. So:

Solve for x:

Therefore, the value of x is 24.  

∠S≅∠F

We will need to find ∠S.

We already know that ∠P is 36.

∠H will be (6x-29). Substitute 24 for x to acquire: (6(24)-29)=144-29=115.

A triangle always totals 180°. Therefore, 115+36+∠S=180 or 151+∠S=180.

Therefore, ∠S=29.

∠F is (3y-1). So:

Solve for y:

Therefore, the value of y is 10.

So, x=24, y=10, and z=17.

And we are done!

45

step-by-step explanation:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17