Tutoring Services: The Community College Survey of Student Engagement reports that 46% of the students surveyed rarely or never use peer or other tutoring resources. Suppose that in reality 40% of community college students never use tutoring services available at their college. In a simulation we select random samples from a population in which 40% do not use tutoring. For each sample we calculate the proportion who do not use tutoring. If we randomly sample 500 students at a time, what will be the mean and standard error of the sampling distribution of sample proportions

Mean = 0.40 and  standard error = 0.0219 of the sampling distribution of sample proportions.

Step-by-step explanation:

Given : The proportion of community college students never use tutoring services available at their college: p= 0.40

Mean of the sampling distribution of sample proportions  = p = 0.40

Since sample size : n= 500

Standard error =

Hence, Mean = 0.40 and  standard error = 0.0219 of the sampling distribution of sample proportions.

the answer is 5/14.

hope this .

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)