Which equation is the inverse of f(x)=LaTeX: \frac{1}{x+2}1 x + 2 A. LaTeX: f^{-1}\left(x\right)=\frac{1}{x}+2f − 1 ( x ) = 1 x + 2 B. LaTeX: f^{-1}\left(x\right)=\frac{1}{x}-2f − 1 ( x ) = 1 x − 2 C. LaTeX: f^{-1}\left(x\right)=2-\frac{1}{x}f − 1 ( x ) = 2 − 1 x D. LaTeX: f^{-1}\left(x\right)=-2-\frac{1}{x} f − 1 ( x ) = − 2 − 1 x

Step-by-step explanation:

Given the function , we are to find the inverse of the function and this can be done y following the simple steps:

Step 1: Replace y with

Step 2: Interchange x with y

Step 3: Make y the subject of the formula;

Step 4: Replace y as

Hence the inverse of the function is

answer: lol haha i'm in flvs too!

but to answer question number 1 would be a.

and number 2 would be c.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0