Mathematics, 03.11.2020 16:50 lizbeth696
Compute the product AB by the definition of the product of matrices, where A and A are computed separately, and by the row-column rule for computing AB. A , B Set up the product A, where is the first column of B. A nothing nothing (Use one answer box for A and use the other answer box for .) Calculate A, where is the first column of B. A nothing (Type an integer or decimal for each matrix element.) Set up the product A, where is the second column of B. A nothing nothing (Use one answer box for A and use the other answer box for .) Calculate A, where is the second column of B.
Answers: 1
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}5\\-2\\\end{array}\right]](/tpl/images/0863/3861/168c0.png)
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}5\\-2\\\end{array}\right] = \left[\begin{array}{ccc}{(-1 * 5 )+ (3* -2)}\\{(1 * 5)+ (4 * -2)}\\{(5 * 5) + (8*-2)}\end{array}\right] = \left[\begin{array}{ccc}{-11}\\{-3}\\{29}\end{array}\right]](/tpl/images/0863/3861/120fe.png)
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}-3\\4\\\end{array}\right]](/tpl/images/0863/3861/98a3b.png)
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}-3\\4\\\end{array}\right] = \left[\begin{array}{ccc}{(-1 * -3 )+ (3* 4)}\\{(1 * -3)+ (4 * 4)}\\{(5 * -3) + (8*4)}\end{array}\right] = \left[\begin{array}{ccc}{15}\\{13}\\{-23}\end{array}\right]](/tpl/images/0863/3861/c1989.png)
![A = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]](/tpl/images/0863/3861/fa54d.png)
![B = \left[\begin{array}{ccc}5&{-3}\\{-2}&4\end{array}\right]](/tpl/images/0863/3861/f2611.png)
, where 
is the first column of matrix B, this shown as 
, where 
is the second column of matrix B, this shown as 
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Compute the product AB by the definition of the product of matrices, where A and A are computed sepa...
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