Robert uses a wheelbarrow to haul wood from his backyard to the back of the neighbor's house, located 80 m away. If he takes 3 breaks evenly when pushing the wheelbarrow the complete distance, at what distance does he take his first break.

26.66 meters

Step-by-step explanation:

The final destination of his neighbor's house is 80 meters away so we can assume that the starting point of Robert's backyard is point 0 meters. Since he takes 3 breaks evenly dispersed between the entire trip, then we simply divide the total distance by 3 in order to distance between each break.

80 / 3 = 26.66 m

Therefore, the distance between each breakpoint is 26.66 meters which also means that the first break is taken at a distance of 26.66 meters. This is because since it is the first break it is added to the starting point of 0 like so...

0 + 26.66 = 26.66 meters

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

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step-by-step explanation: