What are the degrees of freedom for Student's t distribution when the sample size is 19? d. F. = Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19. (Round your answer to three decimal places.)

a) 18

b) 2.101

Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

Or

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation: