Ms. Parker determined that the mean test score in her first-period class was 81 with a standard deviation of 7.06. The mean test score in her second-period class was 88 with a standard deviation of 8.24. Which conclusion can be made about her students' test scores?
A. Period 1 had scores that were less spread out around the median than Period 2.
B. Period 2 had scores that were less spread out around the mean than Period 1.
C. Period 1 had scores that were less spread out around the mean than Period 2.
D. Period 2 had scores that were less spread out around the median than Period 1.

What is the cube root of -1,000p^12q3? -10p^4 -10p^4q 10p^4 10p^4q

A. find the power of the test, when the null hypothesis assumes a population mean of mu = 450, with a population standard deviation of 156, the sample size is 5 and the true mean is 638.47 with confidence intervals of 95 b. find the power of the test, when the null hypothesis assumes a population mean of mu = 644, with a population standard deviation of 174, the sample size is 3 and the true mean is 744.04 with confidence intervals of 95% c. find the power of the test, when the null hypothesis assumes a population mean of mu = 510, with a population standard deviation of 126, the sample size is 10 and the true mean is 529.44 with confidence intervals of 95

Me get the answer and explain to me the steps to solve it would be greatly appreciated : )