What is the equation of the line that passes through the point (4, 9) with a slope of - 5/8 Write the equation in point-slope form.

In this case we have a point,

(

x

,

y

)

and the slope,

m

so all we need is a value for

c

.

Substitute into

y

=

m

x

+

c

−

3

=

5

4

(

8

)

+

c

−

3

=

10

+

c

c

=

−

13

The equation is:

y

=

5

4

x

−

13

Or you can use the formula for the situation where you have a point,

(

x

1

,

y

1

)

and the slope, (m)

→

y

−

y

1

=

m

(

x

−

x

1

)

y

−

(

−

3

)

=

5

4

(

x

−

8

)

y

+

3

=

5

4

x

−

10

y

=

5

4

x

−

13

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6