The perimeters of a rectangle and an equilateral triangle are equal. The length of the rectangle is twice the width, and the side of the triangle is 8 more than the width of the rectangle. Which statements about this scenario are true if
we use the variable w to represent the width of the rectangle?
Check all that apply.

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then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

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