Consider the line y = 3x - 1. Find the equation of the line that is perpendicular to this line and passes through the point (-8, 3)
Find the equation of the line that is parallel to this line and passes through the point (-8, 3).

y = -1/3x + 1/3

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals.

The given line is

y = 3x - 1

This equation is written in the slope-intercept form, y = mx + b, where m is the slope.

slope of given line = m = 3

slope of perpendicular line = -1/3

Now we need the equation of the line with slope -1/3 that passes through the point (-8, 3)

y = mx + b

y = -1/3x + b

3 = (-1/3)(-8) + b

3 = 8/3 + b

9/3 = 8/3 + b

b = 1/3

y = -1/3x + b

y = -1/3x + 1/3

hope this .

r3t40