A model satellite is 7 in wide. If it was built with a scale of 1 in: 2 yd, then how wide is the real satellite?

14yd

Step-by-step explanation:

 Scale of the model:

           1in  to 2yd

This suggest that for every 1in on the model, the actual distance is 2yd.

So;

          A model 7in wide will actually be:

               1in          to     2yd

               7in       will be 7 x 2  = 14yd

do i do it on a graph?

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10