Each of urns I and II has 5 red balls, 3 white balls, and 2 green balls. Urn III has 1 red ball, 1 white ball, and 8 green balls. An urn is selected at random and a ball is drawn. If the ball is green, find the probability that urn III was selected. (Enter your probabilities as fractions.)

The probability of selecting the green ball from urn III is ²/₃

Step-by-step explanation:

Given;

total number of balls in urn I = 10

number of green balls in urn I , = 2

total number of balls in urn II = 10

number of green balls in urn II , = 2

total number of balls in urn III = 10

number of green balls in urn II , = 8

Therefore, the probability of selecting the green ball from urn III is ²/₃

abde or 1,2,4, 5 is the answer

step-by-step explanation:

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction