Matthew found a deposit with a diameter that is 102 times as long as Josef's. How many millimeters long is the diameter of Matthew's deposit? Write your answer in standard form and with number names

See explanation

Step-by-step explanation:

Represent Mathew with M and Joe with J

The question has missing details as diameter found by Joe is missing.

However, we'll assume a value for this.

Let

J = 1440mm

This implies that

M = 102* J

Substitute 1440mm for J

So:

M = 102 * 1440mm

M = 14280mm

The question say the answer must be in standard form.

The form is written as:

a * 10^n

Where 1 ≤ a ≤ 9 and n is an integer

So,

M = 14280mm becomes

M = 1.4280 * 10⁴mm

M = 1.43 * 10⁴mm (approximated)

So, all you need to do is replace actual measurements of Joe's diameter with 1440m.

Other steps remain the same.

jml angle lkj & angle mj = lm