Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return trip, it takes 5 hours. If the rate of the boat in still water and the rate of the current, write an expression that represents the rate of the boat going with the current. Type the expression in the space provided.

22 mph.

Step-by-step explanation:

120 miles/6 hours = 20 mph.

You need to do the same for the boat going with the current.

120 miles/ 5 hours = 24 mph

Now, you need to average the two rates. The "against current" and "with current" should cancel each other out (again, assuming the current is constant) to get the "still water" rate.

20+24/2=44/2= 22 mph

The rate that the boat travels in still water is 22 mph.

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i