find the slope of the tangent line and the equation of the tangent line at the given point, x^2y-5xy^2 6

The complete question is

find the slope of the tangent line and the equation of the tangent line at the given point, at the point (3,1).

Tangent  = 1/23 , equation of tangent  = 23y - x = 20

Step-by-step explanation:

We are given the equation

upon differentiation the given function we get

d () /dt

=

upon substituting x=3 ,y=1 we will get

dy/dx = 1/23

now the equation of the tangent will be

y-1 = 1/23 (x-3)

23 (y-1) = x- 3

23y - 23 = x -3

23y - x = 20

you just switch the numbers basically so it would be 3/17

answer: i ! the answer is   9000 seconds, also d

hope i

-lavira : )