Kim ordered a pizza. He has a $1.00 coupon which will get applied after a weekday discount of 15%. Let the original cost of the pizza, the cost with the coupon discount applied, and the cost with the weekday discount applied. Which expression gives the cost for Kim’s pizza?

c of x plus d of x

d as a function of c of x

c as a function of d of x

c of x times d of x

Correct question is;

Kim ordered a pizza. He has a $1.00 coupon which will get applied after a weekday discount of 15%. Let the X be the original cost of the pizza, C(x) = the cost with the coupon discount applied, and D(x) = the cost with the weekday discount applied.

Which expression gives the cost for Kim’s pizza?

A) C(x) + D(x)

B) D(C(x))

C) C(D(x))

D) C(x) × D(x)

Option C: C(D(x))

Step-by-step explanation:

We are given that;

C(x) = the cost with the coupon discount applied

D(x) = the cost with the weekday discount applied.

Since there is a weekday discount, it means the cost for Kim's pizza will be a function of the discount.

This means that the cost will be C as a function of (D(x)). This can be written as; C(D(x))

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2