Work out the area of a rectangle with base,
b
= 34mm and perimeter,
P
= 88mm.

340mm

Step-by-step explanation:

Area = P × (L ÷ 2) - L × L

But in this case, L for length will be represented by the base which is 34 mm.

P × (L ÷ 2) - L × L

P = 88 mm

88 × 34 ÷ 2 - 34 x 34

= 340 mm

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.