Write the ratio of the area of the actual court to the area of the court in the scale drawing. Part A

Write an equation for the proportional relationship between the drawing's court lengths x in centimeters and the actual court lengths y in centimeters.

Enter the correct equation: y=22.5x

Part B

What are the length and the width in meters of the actual court? Show your work.

Select all the correct answers : length: (22.5)(80) = 1,800 cm = 18 m & width: (22.5)(40) = 900 cm = 9 m

Part C

Write the ratio of the area of the actual court to the area of the court in the scale drawing. help pls :(

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

sine

step-by-step explanation:

explanation:

step-by-step explanation: