Eleanor and Max used two rectangular pieces of plywood, placed end-to-end, to make a long rectangular stage for the school play. One board was 7 feet long, and the other was 6 1/2 feet long. The two pieces of plywood had equal widths. The total area of the stage was 84 3/8 square feet. What was the width of the plywood?

the width of plywood = 6.25 feet wide or  6 1/4 feet wide

Step-by-step explanation:

Step 1

Area of  a rectangular plywood = length x width

Area of Ist Plywood= 7 x w

Area of 2nd  Plywood= 61/2 x w=6.5 xw

But Total Arae of trhe two Plywoods are = 84 3/8 square feet.

Therefore Our equation to solve the problem becomes

Area of Ist Plywood + Area of 2nd  Plywood =84 3/8 square feet.

7w + 6.5w =  84 3/8

13.5w= 84 3/8

w =  84 3/8/13.5

675/8  / 13.5

w=6.25

Therefore the width of plywood = 6.25 feet wide or 6 1/4 feet.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: