The number of salmon swimming upstream to spawn is approximated by the following function: S(x) = -x^3 + 2x^2 + 405x + 4965 where X represents the temperature of the water in degrees Celsius and (6 <= x <= 20
Find the critical value(s) of S(x).
Using the critical values that fall within the domain, apply the 2nd derivative test for the max/min to find the water temperature that produces the maximum number of salmon swimming upstream. (Show work for the 2nd derivative).
The water temperature that produces the maximum number of salmon swimming upstream is degrees Celsius.

The water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.

Step-by-step explanation:

Let , for . represents the temperature of the water, measured in degrees Celsius, and is the number of salmon swimming upstream to spawn, dimensionless.

We compute the first and second derivatives of the function:

(Eq. 1)

(Eq. 2)

Then we equalize (Eq. 1) to zero and solve for :

And all roots are found by Quadratic Formula:

,

Only the first root is inside the given interval of the function. Hence, the correct answer is:

Now we evaluate the second derivative at given result. That is:

According to the Second Derivative Test, a negative value means that critical value leads to a maximum. In consequence, the water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.

answer:

1. 0.04

2. 0.15

step-by-step explanation:

i just finished that assignment for properties of probability distributions.

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.