The area of a trapezoid is 864cm². It has a height of 24 cm, and the length of one of its bases is 30 cm. What is the length of the other base?

The area A of a trapezoid with height h and bases b₁ and b₂ is equal to the average of the bases times the height:

A = (b₁ + b₂) h / 2

We're given A = 864, h = 24, and one of the bases has length 30, so

864 = (b₁ + 30) 24 / 2

864 = (b₁ + 30) 12

864 = (b₁ + 30) 12

72 = b₁ + 30

b₁ = 42

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.