Which of the following equations has exactly one solution? A. 4 x − 4 + 2 x = 6 x − 4 B. 2 ( 4 x + 5 ) = 8 x + 10 C. 4 x − 8 = 4 ( x − 4 ) D. 3 x + 5 = 2 x − 6

D. 3x + 5  = 2x -6

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

w'x is 0.

hope it